Q. 294.7( 3 Votes )

Evaluate: <

Answer :




We know that sin2x + cos2x = 1



We know that sin2x = 2sinxcosx



Divide numerator and denominator by cos22x




We know that 1 + tan2x = sec2x





Substitute tan2x = t


Differentiate with respect to x



dt = 2sec22xdx


Hence





Resubstitute t



Hence

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