Answer :

Given, ∠B = 105°, ∠A = 45°

We know, By angle sum property of a triangle

∠A + ∠B + ∠C = 180°

⇒ 45° + 105° + ∠C = 180°

⇒ ∠C = 30°  

Steps of Construction:

1. Draw a line AC = 6 cm. At A, Draw ∠XAC = 45°

2. At C, Draw ∠YCA = 30°. AX and CY intersect each other at B and given ΔABC is ready.

3. Draw an acute angle ∠CAZ below AC.

4. Mark points A1, A2, …, A5 on BZ such that AA1 = AA2 = … = AA5.

5. Join A5

6. Draw a line A4C’ || A5C from A4 such that point C’ lies on line AC and from point C’, draw a line B’C’ || BC such that point B’ lies on AB.


ΔAB’C’ is required triangle.

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