Q. 295.0( 1 Vote )
Given, ∠B = 105°, ∠A = 45°
We know, By angle sum property of a triangle
∠A + ∠B + ∠C = 180°
⇒ 45° + 105° + ∠C = 180°
⇒ ∠C = 30°
Steps of Construction:1. Draw a line AC = 6 cm. At A, Draw ∠XAC = 45°
2. At C, Draw ∠YCA = 30°. AX and CY intersect each other at B and given ΔABC is ready.
3. Draw an acute angle ∠CAZ below AC.
4. Mark points A1, A2, …, A5 on BZ such that AA1 = AA2 = … = AA5.
5. Join A5
6. Draw a line A4C’ || A5C from A4 such that point C’ lies on line AC and from point C’, draw a line B’C’ || BC such that point B’ lies on AB.
ΔAB’C’ is required triangle.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Glimpses of India39 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation