Answer :

We have to construct a triangle ABC in which BC = 6 cm, AB = 5 cm also we have to construct another triangle whose sides are times the corresponding sides of triangle ABC. The figure for the following situation is as follows:

The step of constructions for the above figure are as follows:

(i) Firstly, we have to draw a triangle ABC having AB = 5 cm, BC = 6 cm and angle ABC = 60^{o}

(ii) Secondly, we have to draw a ray BX downwards that makes an acute angle with BC

(iii) After this locate 4 points B_{1}, B_{2}, B_{3}, B_{4} on BX such that BB_{1} = B_{1}B_{2} = B_{2}B_{3} = B_{3}B_{4}

(iv) Now Join CB_{4} and draw a line C’B_{3} CB_{4} from B_{3} such that it will intersect BC at C’

(v) At last, from C draw A’C’ AC which intersects AB at B’

∴ ∠ABC is the required triangle.

The justification for the given solution:

Form AA rule of similarly we have

_{∴} (i)

Also, (ii)

Hence, from equation (i) and (ii) we have:

Rate this question :