Q. 295.0( 4 Votes )

# Check which of the following are solutions of the equation 2x – 3y = 6.

(i) (3, 0) (ii) (0, 2)

(iii) (2, 6) (iv) (6, 2)

Answer :

(i) (3, 0)

2x – 3y = 6

LHS = 2x – 3y

Where x = 3 and y = 0,

Putting these values in 2x – 3y

⇒ 2×3 – 3×0

⇒ 6 – 0

⇒ 6 = RHS

Since, LHS = RHS therefore, (3, 0) satisfies 2x – 3y = 6

(ii) (0,2)

2x – 3y = 6

LHS = 2x – 3y

Where x = 0 and y = 2,

Putting these values in 2x – 3y

⇒ 2×0 – 3×2

⇒ 0 – 6

⇒ – 6 ≠ RHS

Since, LHS ≠RHS therefore, (0, 2) does not satisfy 2x – 3y = 6

(iii) (2, 6)

2x – 3y = 6

LHS = 2x – 3y

Where x = 2 and y = 6,

Putting these values in 2x – 3y

⇒ 2×2 – 3×6

⇒ 4 – 18

⇒ – 14≠ RHS

Since, LHS ≠RHS therefore, (2, 6) does not satisfy 2x – 3y = 6

(iv) (6, 2)

2x – 3y = 6

LHS = 2x – 3y

Where x = 6 and y = 2,

Putting these values in 2x – 3y

⇒ 2×6 – 3×2

⇒ 12 – 6

⇒ 6 = RHS

Since, LHS = RHS therefore, (6, 2) satisfies 2x – 3y = 6

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