# Check which of the following are solutions of the equation 2x – 3y = 6.(i) (3, 0) (ii) (0, 2)(iii) (2, 6) (iv) (6, 2)

(i) (3, 0)

2x – 3y = 6

LHS = 2x – 3y

Where x = 3 and y = 0,

Putting these values in 2x – 3y

2×3 – 3×0

6 – 0

6 = RHS

Since, LHS = RHS therefore, (3, 0) satisfies 2x – 3y = 6

(ii) (0,2)

2x – 3y = 6

LHS = 2x – 3y

Where x = 0 and y = 2,

Putting these values in 2x – 3y

2×0 – 3×2

0 – 6

– 6 RHS

Since, LHS ≠RHS therefore, (0, 2) does not satisfy 2x – 3y = 6

(iii) (2, 6)

2x – 3y = 6

LHS = 2x – 3y

Where x = 2 and y = 6,

Putting these values in 2x – 3y

2×2 – 3×6

4 – 18

– 14 RHS

Since, LHS ≠RHS therefore, (2, 6) does not satisfy 2x – 3y = 6

(iv) (6, 2)

2x – 3y = 6

LHS = 2x – 3y

Where x = 6 and y = 2,

Putting these values in 2x – 3y

2×6 – 3×2

12 – 6

6 = RHS

Since, LHS = RHS therefore, (6, 2) satisfies 2x – 3y = 6

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