# A park in the sha

rom the given figure, it is clear that:

BCD is a right triangle

BD = = = = = 13 m

Now, area of = = = = 6 × 5 = 30 m2

Let the sides of the triangle be: a = 9 m, b = 8 m and c = 13 m

s = = = = 15 m

Thus, by using Heron’s formula we get:

Area of = = = = = = 6 × 5.9 = 35.4 m2

Area of quadrilateral ABCD = Area of + Area of = 30 + 35.4

= 65.4 m2

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