# A park in the sha

rom the given figure, it is clear that:

BCD is a right triangle

BD =

=

=

=

= 13 m

Now, area of =

=

=

= 6 × 5 = 30 m2

Let the sides of the triangle be: a = 9 m, b = 8 m and c = 13 m

s =

=

= = 15 m

Thus, by using Heron’s formula we get:

Area of

=

=

=

=

=

= 6 × 5.9 = 35.4 m2

Area of quadrilateral ABCD = Area of + Area of

= 30 + 35.4

= 65.4 m2

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