Q. 294.0( 2 Votes )

A park in the sha

Answer :

rom the given figure, it is clear that:

BCD is a right triangle


BD =


=


=


=


= 13 m


Now, area of =


=


=


= 6 × 5 = 30 m2


Let the sides of the triangle be: a = 9 m, b = 8 m and c = 13 m


s =


=


= = 15 m


Thus, by using Heron’s formula we get:


Area of


=


=


=


=


=


= 6 × 5.9 = 35.4 m2


Area of quadrilateral ABCD = Area of + Area of


= 30 + 35.4


= 65.4 m2


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