# Using integration

Plotting the points, we get, Let us first find the equation of sides of the triangle,

Equation of line passing from points P(x1, y1) and Q(x2, y2) is given by: Therefore,

Equation of AB: y – 5 = (x – 2)

y = x + 3

Equation of BC:   Equation of AC:   Now, let us look at the limits that we have to take, Therefore,   Area = 21 square units.

OR

Given Curves: C1: x2 + y2 = 8x

C2: y2 = 4x

Let us find the intersection point of the curves.

Putting the value of y2 from second curve in first curve,

x2 + 4x = 8x

x2 – 4x = 0

x(x – 4) = 0

x = 0 or x = 4

And,

y2 = 4.0, y = 0

y2 = 4.4, y = ± 4

On plotting we will get, Area required is shared in the given figure,

Area required will be found by: Therefore,

Area required = Area OPC + Area PCQ

For parabola, y = ±√4x

y = ±2√x

Area OPC    Now, for circle, Area of PCQ    Now, we know that, Therefore,

Area PCQ    = 4π Rate this question :

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