Q. 284.8( 4 Votes )

To fill a swimmin

Answer :

Let the bigger pipe fill the tank in x hrs.

the smaller pipe fills the tank in (x + 10) hrs.

Given that the bigger pipe is used for 4hrs and smaller pipe for 9hrs and together they fill half the tank.


2(13x + 40)=x(x + 10)

26x + 80=x2 + 10x


x2-20x + 4x-80=0

x(x-20) + 4(x-20)=0

(x + 4)(x-20)=0

x=20 or x=-4(rejected)

Therefore, The time taken by larger pipe=20hrs.

And time taken by smaller pipe=20 + 10=30hrs

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