Given:n=5q=0.3P(x=4)=?P=1-0.3=0.7P(x=r)= nCr pr qn-rP(x=4)= 5C4 p4 q=5C4 (0.7)4 (0.3)

Q. 285.0( 1 Vote )

Mark the correct A. ⁵C₄ (0.7)⁴ (0.3)

B. ⁵C₁ (0.7) (0.3)⁴

C. ⁵C₄ (0.7) (0.3)⁴

D. (0.7)⁴ (0.3)

Answer :

Given:

n=5

q=0.3

P(x=4)=?

P=1-0.3=0.7

P(x=r)= ⁿC_r p^r q^n-r

P(x=4)= ⁵C₄ p⁴ q

=⁵C₄ (0.7)⁴ (0.3)

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Mark the correct A. 5C4 (0.7)4 (0.3)B. 5C1 (0.7) (0.3)4C. 5C4 (0.7) (0.3)4D. (0.7)4 (0.3)