Q. 285.0( 1 Vote )

# The diameter of t

Given: Diameter of two circular ends of a bucket are 44 cm and 24 cm, and the height of the bucket is 35 cm.

Bucket is in the shape of frustum.

Let V be the Volume of the Bucket(Frustum)

Volume of the frustum is given by: × h × (R2 + r2 + Rr) (here r and R are the radii of smaller and larger circular ends respectively)

V = × h × (R2 + r2 + R × r)

V = × 35 × (222 + 122 + 22 × 12) (diameters are 44 and 24 cm, their radii are 22cm and 12cm respectively)

V = × 35 × (484 + 144 + 264) = × 35 × (892)

V = × 35 × (892) = 32706.6 cm3 = 32.7 litres ( 1000cm3 = 1 litre)

The capacity of the bucket is: 32.7 litres

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