Q. 283.7( 3 Votes )

Red queens and bl

Answer :

Given 2 red queens and 2 black jacks are removed from the pack of 52 playing cards.


Then, remaining number of cards = 52 – 4 = 48


We know that probability of an event E, P (E)


(i) Number of kings = 4


P (a king) = 4/48 = 1/12


(ii) Since 2 red queens are removed, number of red colour cards remaining = 26 – 2 = 24


P (of red colour) = 24/48 = 1/2


(iii) Since 2 red queens and 2 black jacks are removed, number of face cards remaining = 12 – 4 = 8


P (a face card) = 8/48 = 1/6


(iv) There are only 2 queens remaining.


P (a queen) = 2/48 = 1/24


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