Answer :

Consider ΔABC such that AC^{2} =AB^{2} +BC^{2}

To prove : ∠B = 90°

Construction : We construct another ΔPQR right angled at Q such that PQ = AB and QR = BC

In ΔPQR , by Pythagoras theorem, we have

In Δ ABC & ΔPQR

AB = PQ [by construction]

BC = QR [by construction]

AC = PR [Proved above]

∠B = ∠Q = 90° [by CPCT]

Hence proved

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