Q. 28

# If the length of

Given, A trapezium is given, and the length of three sides is 10cm.

To Find: Find the area of a trapezium,

Explanation: Let Assume, ABCD is a trapezium Now, Make a construction DP perpendicular AB and CQ perpendicular AB

Now, Let AP = x cm , then BQ = x cm

So,   Area of trapezium ABCD = Area of ABCD   For the maximum area, we know  x2 + 5x - 50 = 0

x2 + 10x - 5x - 50 = 0

x(x + 10) - 5(x + 10) = 0

(x + 10)(x - 5) = 0

X = 5, - 10

We will neglect negative values

Now, (     Now, Area at x = 5    Area of the trapezium is maximum when x = 5

A = (10 + 5)  cm2

Hence, The Area of the trapezium is Rate this question :

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