# If one root of th

3x2 + px + 4 = 0

3(2/3)2 + p(2/3) + 4 = 0

4/3 + 2p/3 + 4 = 0

p = -8

3x2 - 8x + 4 = 0

By middle term splitting,

3x2 - 6x - 2x + 4 = 0

x = 2/3 or x = 2

Hence, x = 2

OR

α + β = 5 ----(1)

α – β = 1 ----(2)

Solving (1) and (2), we get

α = 3 and β = 2

also, αβ = 6

or 3(k - 1) = 6

k – 1 = 2

k = 3

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