# Find equation of

The equations of the given lines are

9x + 6y – 7 = 0 ---------------- (1)

3x + 2y + 6 = 0 ---------------- (2)

Let P (h, k) be the arbitrary point that is equidistant from (1) and (2).

The perpendicular distance of P(h, k) from line (1) is given by

The perpendicular distance of P(h, k) from line (2) is given by

Since, P (h, k) is equidistant from lines (1) and (2),

Thus,

or

So, when is not possible as

which is not at all possible

And when

9h + 6k – 7 = -9h – 6k – 18

18h + 12k +11 = 0

Therefore, the required equation of the line is 18h + 12k +11 = 0.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Find the values oRD Sharma - Mathematics

The vertices of aRD Sharma - Mathematics

For specifying a Mathematics - Exemplar

If the line <spanMathematics - Exemplar

Equations of diagMathematics - Exemplar

If the coordinateMathematics - Exemplar