Q. 284.7( 3 Votes )

# Find equation of the line which is equidistant from parallel lines 9x + 6y – 7 = 0 and 3x + 2y + 6 = 0.

Answer :

The equations of the given lines are

9x + 6y – 7 = 0 ---------------- (1)

3x + 2y + 6 = 0 ---------------- (2)

Let P (h, k) be the arbitrary point that is equidistant from (1) and (2).

The perpendicular distance of P(h, k) from line (1) is given by

The perpendicular distance of P(h, k) from line (2) is given by

Since, P (h, k) is equidistant from lines (1) and (2),

Thus,

or

So, when is not possible as

which is not at all possible

And when

⇒ 9h + 6k – 7 = -9h – 6k – 18

⇒ 18h + 12k +11 = 0

Therefore, the required equation of the line is 18h + 12k +11 = 0.

Rate this question :

Find the values of θ and p, if the equation x cos θ + y sin θ = p is the normal form of the line .

RD Sharma - MathematicsThe vertices of a triangle are (6, 0), (0, 6) and (6, 6). The distance between its circumcentre and centroid is

RD Sharma - MathematicsFor specifying a straight line, how many geometrical parameters should be known?

Mathematics - ExemplarIf the line passes through the points (2, –3) and (4, –5), then (a, b) is

Mathematics - Exemplar