Answer :

(a) Amount of milk one container can hold = Volume of frustum

As we know

volume of frustum of a cone

Where, h = height, r_{1} and r_{2} are radii of two ends (r_{1} > r_{2})

For given container,

Radius of top, r_{1} = 40 cm

Radius of bottom, r_{2} = 20 cm

Height of each container, h = 30 cm

Using these values,

We have.

Now,

1000 cm^{3} = 1 L

⇒ 88000 cm^{3} = 88 L

No of container required

(ii) Cost = Amount of milk × Rate of milk

Cost = 880 × 35 = 30800 RS

(iii) The organization empathies with the victims and aspires to help the needy ones, the agency portrays the values of kindness and humanity.

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