Q. 275.0( 1 Vote )

# Using integration

Let the vertices be A(−2,1), B(0,4), and C(2,3).

The equation of AB is;

3x − 2y + 8 = 0

The equation of BC is;

x + 2y − 8 = 0

The equation of AC is;

x − 2y + 4 = 0

Required area =

= 0 + 0 − 3 + 8 + 1 + 8 − 0 − 0 − (1 + 4 − 1 + 4)

= 4 sq.unit

OR

By solving the equations x2 + y2 = 16 and x = √3 y

3y2 + y2 = 16

y = 2 x = √3 y = x√3

So the point of intersection is (2√3,2)

Required Area

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Draw a rough sketMathematics - Exemplar

Compute the area Mathematics - Exemplar

Using integrationMathematics - Board Papers

Find the area of Mathematics - Board Papers

Find the area of Mathematics - Exemplar

Evaluate <span laMathematics - Board Papers

The area of the rMathematics - Exemplar

Find the area bouMathematics - Exemplar