Q. 274.7( 9 Votes )

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Answer :


Given: PT and PS are tangents from an external point P to the circle with center O.


To Prove: PT = PS


Const: Join O to P, T, and S


Proof: In Δ OTP and Δ OSP


OT=OS …[radii of the same circle


OP=OP …[Common


OTP = OSP …[Each 90 �


OTP = OSP …[R.H.S. congruence condition


PT = PS (by CPCT)


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