Q. 275.0( 1 Vote )

# Match the followi

The parts of the question are solved below:

a. Given: In ABC, AB = AC and A=50°

Thus, B = C

Now, A + B + C = 180° (The angle sum property of triangle)

50 + 2B = 180°

2B = 130°

C = B = 65°

b. As per the question,

Let the vertical angle be A and B = C

Now, A + B + C = 180° (The angle sum property of triangle)

130 + 2B = 180°

2B = 50°

C = B = 25°

c. We know that, the sum of three altitudes of a triangle ABC is less than its perimeter.

d. Here, ABCD is a square and EDC is a equilateral triangle.

ED = CD = AB = BC = AD = EC

In ΔECB,

EC = BC

C = B = x

ECD = 60° and DCB = 90°

ECB = 60° + 90°

= 150°

Now, x + x + 150° = 180°

2x = 30°

x = 15°

∴∠EBC = 15°

a = r, b = s, c = p, d = q

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Revision on Angle sum Property of Triangles44 mins
Concentration of a Solution - Part 246 mins
Concentration of a Solution - Part 142 mins
Variation in g with Rotation of Earth42 mins
Arc of Circle And Related IMP Qs40 mins
Surface Area and Volume of solids Revision43 mins
Circles- All kinds of Questions36 mins
Significance of Newton's Laws in daily life42 mins
Variation in g due to Height and Depth33 mins
Structural Organisation In Animals-II57 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Prove that the anRS Aggarwal & V Aggarwal - Mathematics

If the sides of aRD Sharma - Mathematics

D is any point onNCERT Mathematics Exemplar

In a triangle RD Sharma - Mathematics

In Δ ABCRD Sharma - Mathematics

In Δ PQRRD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

Prove that the peRD Sharma - Mathematics

In Fig. 10.25, <iRD Sharma - Mathematics

In a <span lang="RD Sharma - Mathematics