Q. 275.0( 1 Vote )

# #Mark the correct alternative in each of the followingLet f(x) = 2x3 – 3x2 – 12x + 5 on [–2, 4]. The relative maximum occurs at x =A. –2B. –1C. 2D. 4

f(x) = 2x3 – 3x2 – 12x + 5, x[-2,4]

Differentiating f(x) with respect to x, we get

f’(x)= 6x2 – 6x – 12=6(x+1)(x-2)

Differentiating f’(x) with respect to x, we get

f’’(x)=12x-6

For maxima at x=c, f’(c)=0 and f’’(c)<0

f’(x)=0 x=-1 or 2

f’’(-1)=-18<0 and f’’(2)=18>0

Hence, x=-1 is the point of local maxima.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
How to find Maxima & Minima?43 mins
Interactive quiz on maxima and minima48 mins
Maxima & Minima in an interval60 mins
Questions Based on Maxima & Minima57 mins
When does a Maxima or Minima occur?48 mins
Interactive quizz on tangent and normal, maxima and minima43 mins
Super 10 Question: Check Your Knowledge of Maxima & Minima (Quiz)45 mins
Questions based on Maxima & Minima in an interval59 mins
Check your Knowlege of Maxima & Minima ( Challenging Quiz)60 mins
Human Evolution | An Important Concept40 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses