Q. 275.0( 2 Votes )

# In a hockey match

Answer :

As captain of team A has started to throw the die, he may win in the first throw or third or fifth and so on.

Team B can win in 2nd throw or 4th or 6th and so on

As probability of getting 6 on a die = 1/6 = P(6)

P(6’) represents event of not getting 6 = 5/6

Let P(A) represents the probability that team A wins the game and P(B) represents the probability that team B wins the game.

P(A) = P(6) + P(6’)P(6’)P(6) + P(6’)P(6’)P(6’)P(6’)P(6)+…to ∞

P(A) = P(A) = Clearly it forms an infinite GP and sum of infinite GP is given by where a is the first term and r is common ratio.

Here a = 1 and r = (5/6)2

P(A) = Similarly,

P(B) = P(6’)P(6) + P(6’)P(6’)P(6’)P(6) + … to ∞

P(B) = P(B) = Clearly it forms an infinite GP and sum of infinite GP is given by where a is the first term and r is common ratio.

Here a = 1 and r = (5/6)2

P(B) = Clearly, P(A) > P(B)

Hence, there is more chance of winning of team A.

Umpire’s decision is unfair. He has favoured team A.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

A bag contains 6 RD Sharma - Volume 2

A man is known toMathematics - Board Papers

A bag contaRD Sharma - Volume 2

Three persons A, Mathematics - Board Papers

Bag I contains 3 Mathematics - Board Papers

A speaks trRD Sharma - Volume 2

Two cards aRD Sharma - Volume 2

A bag contaRD Sharma - Volume 2

Kamal and MRD Sharma - Volume 2

Two balls aRD Sharma - Volume 2