Q. 275.0( 4 Votes )

From a point P on

Answer :

Image

The figure demonstrates the condition given in the question.


We have to find the distance between D and C.


In Δ BCD,


( tan θ = Height/Base)


y = x3 m ………….(1)


In Δ ABC,


( tan θ = Height/Base)



5 + x = y3


5 + x = (x3)(3) (From eq 1)


5 + x = 3x


2x = 5


x = 2.5m


Height of tower = x = 2.5m


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