Q. 275.0( 1 Vote )

Find the distance

Answer :

A, B and C are 3 points on the plane.

Normal to the plane, N = (A – B) × (A – C)

So, the Cartesian equation of the plane is of the form

⇒ 12x - 16y + 12z = d

Since (3, -1, 2) is a point on the plane,

⇒ 36 + 16 + 24 = d

⇒ d = 76

Equation of plane is

⇒ 3x – 4y + 3z – 19 = 0

Distance of point P (6, 5, 9) from the plane is

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