# Evaluate the foll

Let Using property       We know that cos 2x = 1 – 2sin2x  Divide by cos2x in numerator and denominator  We know that 1 + tan2x = sec2x  Let tan x = t

The limits will also change

When   and   So, the limits will be -1 to 1

Now, sec2x dx = dt

Hence   We know that      Hence OR

Here f(x) = 3x2 – 2x + 4

Expressing integral as limit of sum Where    Let us find f (a + rh)

f(a + rh) = 3(a + rh)2 – 2(a + rh) + 4

f(a + rh) = 3(a2 + 2arh + r2h2) – 2a – 2rh + 4

f(a + rh) = 3a2 + 6arh + 3r2h2 – 2a – 2rh + 4

Here a = -2 and b = 2

b – a = 2 – (-2) = 4 and    Put this value of f(a + rh) in (i)  Since ,  And,         Put the limit As  Rate this question :

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Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2

Evaluate the follRD Sharma - Volume 2