Q. 275.0( 5 Votes )

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Answer :

Let x and y be the number of items produced per day of model A and model B respectively.


Then, 2x+y≤40


2x+3y≤80


x≥0, y≥0


We have to maximize Z:15x+10y



Since the area is bounded, therefore the maximum value will occur on corner points.


When x=0 and y=0, Z=0


When x=20 and y=0, Z=300


When x=0 and ,


When x=10 and y=20, Z=350


Hence the maximum profit that the manufacturer can make in a day is ₹350, when the number of items of model A will be 10 and of model B will be 20.


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