Q. 275.0( 5 Votes )

<span lang="EN-US

Answer :

Let x and y be the number of items produced per day of model A and model B respectively.

Then, 2x+y≤40


x≥0, y≥0

We have to maximize Z:15x+10y

Since the area is bounded, therefore the maximum value will occur on corner points.

When x=0 and y=0, Z=0

When x=20 and y=0, Z=300

When x=0 and ,

When x=10 and y=20, Z=350

Hence the maximum profit that the manufacturer can make in a day is ₹350, when the number of items of model A will be 10 and of model B will be 20.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

A manufacturer prMathematics - Board Papers

A retired person Mathematics - Board Papers

A manufacturing cMathematics - Board Papers