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Let x and y be the number of items produced per day of model A and model B respectively.

Then, 2x+y≤40

2x+3y≤80

x≥0, y≥0

We have to maximize Z:15x+10y

Since the area is bounded, therefore the maximum value will occur on corner points.

When x=0 and y=0, Z=0

When x=20 and y=0, Z=300

When x=0 and ,

When x=10 and y=20, Z=350

Hence the maximum profit that the manufacturer can make in a day is ₹350, when the number of items of model A will be 10 and of model B will be 20.

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