Let x and y be the number of items produced per day of model A and model B respectively.
We have to maximize Z:15x+10y
Since the area is bounded, therefore the maximum value will occur on corner points.
When x=0 and y=0, Z=0
When x=20 and y=0, Z=300
When x=0 and ,
When x=10 and y=20, Z=350
Hence the maximum profit that the manufacturer can make in a day is ₹350, when the number of items of model A will be 10 and of model B will be 20.
Rate this question :