Q. 265.0( 1 Vote )

# Using integration

Answer :

Plotting the points, we get, Let us first find the equation of sides of the triangle,

Equation of line passing from points P(x1, y1) and Q(x2, y2) is given by: Therefore,

Equation of AB: y – 5 = (x – 2)

y = x + 3

Equation of BC:   Equation of AC:   Now, let us look at the limits that we have to take, Therefore, Area = 21 square units.

OR

Given Curves: C1: x2 + y2 = 8x

C2: y2 = 4x

Let us find the intersection point of the curves.

Putting the value of y2 from second curve in first curve,

x2 + 4x = 8x

x2 – 4x = 0

x(x – 4) = 0

x = 0 or x = 4

And,

y2 = 4.0, y = 0

y2 = 4.4, y = ± 4

On plotting we will get, Area required is shared in the given figure,

Area required will be found by: Therefore,

Area required = Area OPC + Area PCQ

For parabola, y = ±√4x

y = ±2√x

Area OPC    Now, for circle, Area of PCQ    Now, we know that, Therefore,

Area PCQ    = 4π Rate this question :

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