Q. 265.0( 1 Vote )

In a rhombus ABCD, if ∠ACB =40°, then ∠ADB =A. 70°B. 45°C. 50°D. 60°

The diagonals in a rhombus are perpendicular,

So,

BPC = 90o

From triangle BPC,

The sum of angles is 180°

So,

CBP = 180o – 40o – 90o

= 50°

Since, triangle ABC is isosceles

We have,

AB = BC

So,

ACB = CAB = 40o

Again from triangle APB,

PBA = 180o – 40o – 90o

= 50o

Again, triangle ADB is isosceles,

So,

ADB = DBA = 50o

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