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# Find the particular solution of the differential equation y ≠ 0 given that x = 0 when [CBSE 2013]

Given  This is a first order linear differential equation of the form Here, P = cot y and Q = 2y + y2cot y

The integrating factor (I.F) of this differential equation is,  We have  I.F = sin y [ elog x = x]

Hence, the solution of the differential equation is,      Recall    x sin y = y2 sin y + c  x = y2 + c cosec y

However, when , we have x = 0.    By substituting the value of c in the equation for x, we get  Thus, the solution of the given differential equation is Rate this question :

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