Q. 264.5( 2 Votes )

# A mason constructs a wall of dimension (270 cm × 300cm × 350cm) with bricks, each of size (22.5cm × 11.25cm × 8.75cm) and it is assumed that 1/8 space is covered by the mortar. Number of bricks used to construct the wall is

A. 11000

B. 11100

C. 11200

D. 11300

Answer :

Given: A wall of dimension (270 cm × 300cm × 350cm).

A wall of dimension (22.5cm × 11.25cm × 8.75cm).

space is covered by the mortar.

Here volume of the wall is covered by mortar, ∴ 1 – = volume of the wall is covered by bricks.

Volume of the cuboid is given by: lbh (here l, b, h are length , breadth, height respectively).

Let V_{1} be the volume of the wall.

∴ V_{1} = l × b × h = 270 × 300 × 350

⇒ V_{1} = 270 × 300 × 350 = 28350000 cm^{2}

Let V_{2} be the volume of the brick.

∴ V_{2} = l × b × h = 22.5 × 11.25 × 8.75

⇒ V_{2} = 22.5 × 11.25 × 8.75 = cm^{2}

Let ‘n’ be the number of bricks required to occupy volume of the wall.

∴ n × = 28350000 ×

⇒ n = 28350000 × × = 11200

∴ n = 11200

That is 11200 bricks required to occupy volume of the wall.

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