Q. 265.0( 1 Vote )

Mark the correct A.

B.

C.

D.

Answer :

Given:


Total pens=100


Defective pens=10


n=5


P(atmost one non-defective pen)=?


P(defective pens



=p



P(atmost one non-defective pen)=p(x<10)


=p(x=0)+p(x=1)


= 5C0 p0 q5+5pq4



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