Given:Total pens=100Defective pens=10n=5P(atmost one non-defective pen)=?P(defective pens=pP(atmost one non-defective pen)=p(x<10)=p(x=0)+p(x=1)= 5C0 p0 q5+5pq4

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Class 12th RD Sharma - Volume 2 33. Binomial Distribution

Answer :

Given:

Total pens=100

Defective pens=10

n=5

P(atmost one non-defective pen)=?

P(defective pens

P(atmost one non-defective pen)=p(x<10)

=p(x=0)+p(x=1)

= ⁵C₀ p⁰ q⁵+5pq⁴

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Mark the correct A. B. C. D.

Mark the correct A.

B.

C.

D.