Q. 265.0( 2 Votes )

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Answer :

given: 20 cards numbered from 1-20

formula: one card is drawn at random therefore total possible outcomes are 20C1

therefore n(S)=20C1=20

(i) let E be the event that the number on the drawn card is a multiple of 4

E= {4, 8, 12, 16, 20}

n(E)= 5C1=5  (ii) let E be the event that the number on the drawn card is not a multiple of 4

E’ be the event that the number on the drawn card is a multiple of 4

E’= {4, 8, 12, 16, 20}

n(E)= 5C1=5  P(E)=1-P(E’) (iii) let E be the event that the number on the drawn card is odd

E= {1, 3, 5, 7, 9, 11, 13, 15, 17, 19}

n(E)= 10C1=10  (iv) let E be the event that the number on the drawn card is greater than 12

E= {13, 14, 15, 16, 17, 18, 19, 20}

n(E)= 8C1=8  (v) let E be the event that the number on the drawn card is a multiple of 5

E= {5, 10, 15, 20}

n(E)= 4C1=4  (vi) let E be the event that the number on the drawn card is not divisible by 6

let E’ be the event that number on the drawn card is divisible by 6

E’= {6, 12, 18}

n(E’)= 3C1=3  P(E)=1-P(E’) Rate this question :

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