Answer :

Let the tap of the smaller diameter and larger diameter fills the tank alone in x and (x – 10) hours respectively.


In 1 hour, the tap of the smaller diameter can fill 1/x part of the tank.


In 1 hour, the tap of the larger diameter can fill 1/(x – 10) part of the tank.


Two water taps together can fill a tank in hours = 75/ 8 hours.


But in 1 hour the taps fill 8/75 part of the tank.





4x2 – 40x = 75x – 375


4x2 – 115x + 375 = 0


4x2 – 100x – 15x + 375 = 0


4x(x – 25) – 15( x – 25) = 0


(4x -15)( x – 25) = 0


x = 25, 15/4


Taking x = 15 / 4


x – 10 = -25 /4 (But, time cannot be negative)


Now, taking x = 25


x – 10 = 15


Larger diameter of the tap can the tank 15 hours and smaller diameter of the tank can fill


the tank in 25 hours.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Solve the followiKC Sinha - Mathematics

Solve each of theRS Aggarwal - Mathematics

If 2x – 3y = 7 anRD Sharma - Mathematics

A plane left 30 mKC Sinha - Mathematics

A boat goes 16 kmKC Sinha - Mathematics