Answer :

We know that cos2x = 1 – sin2x

(a2sin2x + b2cos2x) = a2sin2x + b2(1 – sin2x)


= (a2 – b2)sin2x + b2



Let, sin2x = t


Differentiating both sides with respect to x



= sin 2x


dt = sin2x dx



Use formula



Again, put t = sin2x



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