Q. 255.0( 4 Votes )

Using integration

Answer :


To find the point of intersection equate the values of y to get,


2x + 1 = 3x + 1


x = 0


So, y = 3(0) + 1


= 1


Now when x = 4,


Y = 3(4) + 1


= 12+ 1


= 13


Also, when x = 4,


Y = 2(4) + 1


= 8 + 1


= 9


Hence the points of intersection are (0,1),(4,9),(4,13).


Area ACB = Area OLBAO – Area OLCAO



{The limits for both the brackets are 0 to 4}


= (24 + 4) - (16 + 4)


= 8 units


Hence the required area is 8 square units.


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