Q. 25

Mark the correct alternative in each of the following:

The probability that in a year of 22nd century chosen at random, there will be 53 Sundays, is

A. 3/28

B. 2/28

C. 7/28

D. 5/28

Answer :

P(53 Sundays) = P(Leap Years)P(53 Sundays in a Leap Year) + P(Non-Leap Years)P(53 Sundays in a Non-Leap Year) (1)


Now,


P(53 Sundays in a Leap Year) (52 Weeks + 2 days Saturday + Sunday or Sunday + Monday)


P(53 Sundays in a non-Leap Year) (52 Weeks + 1 day)


Next step in solving this problem requires the total number of leap years in 22nd Century.


Leap Years = 24


Non Leap Years = 76


P(Leap Year)


P(Non-Leap Year)


We now have all the required information, using equation (1) we get





Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :