Q. 255.0( 1 Vote )

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Answer :

Given that f : R R, f(x) = x2


Let f(x)=y(x)


x2 = y2


x = ±y


So, it is not one-one.


f(x) = y


x2 = y


x = ±√y


But co domain is R.


Hence, f is neither injective nor surjective.

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