Q. 255.0( 1 Vote )

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Answer :

Given that f : R R, f(x) = x2

Let f(x)=y(x)

x2 = y2

x = ±y

So, it is not one-one.

f(x) = y

x2 = y

x = ±√y

But co domain is R.

Hence, f is neither injective nor surjective.

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