Answer :


In the given Figure, Join OP


Now, OP AB


[Tangents drawn at a point on circle is perpendicular to the radius through point of contact]


∴∠OPA = 90°


OPQ + APQ = 90°


OPQ + 58° = 90°


[Given, APQ = 58°]


OPQ = 32°


In OPQ


OP = OQ


[Radii of same circle]


OQP = OPQ


[Angles opposite to equal sides are equal]


PQB = 32°


[As OQP = PQB ]

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