Q. 255.0( 2 Votes )

# In the given figure, AB || CD. If ∠APQ = 70° and ∠PRD = 120°, then ∠QPR = ?

A. 50°

B. 60°

C. 40°

D. 35°

Answer :

APQ =PQR =70^{o}

Now, in triangle PQR, we have

PQR + PRQ + QPQ =180^{o}

70 + 60 + QPQ =180^{o}

QPQ =180^{o} – 130^{o}

=50^{o}

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