Answer :
Given that,
AB ‖ CD
Produce P to Q so that PQ ‖ AB ‖ CD
∠BAP + ∠APQ = 180o (Interior angle)
132o + ∠APQ = 180o
∠APQ = 48o (i)
∠APC = ∠APQ + ∠QPC
148o = 48o + ∠QPC [From (i)]
∠QPC = 100o
∠QPC + ∠PCD = 180o (Interior angles)
100o + ∠PCD = 180o
∠PCD = 80o
∠PCD + x = 180o (Linear pair)
80o + x = 180o
x = 100o
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