Q. 25

Given 15 cot A =8

Answer :

15 cot A = 8, find sin A and sec A.


Cot A =8/15




By Pythagoras Theorem


AC2 =AB2 +BC2


AC =


AC = 17x


Sin A = 15/17


Cos A =8/17 Sec A = 17/8


OR


By Pythagoras Theorem


QR = cm


QR = 5 cm


tan P = 5/12


cot R =5/12


tan P -Cot R = 5/12 – 5/12 = 0


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