15 cot A = 8, find sin A and sec A.Cot A =8/15By Pythagoras TheoremAC2 =AB2 +BC2AC = AC = 17xSin A = 15/17Cos A =8/17 ⇒ Sec A = 17/8ORBy Pythagoras TheoremQR = cmQR = 5 cmtan P = 5/12cot R =5/12tan P -Cot R = 5/12 – 5/12 = 0

Q. 25

Given 15 cot A =8

Class 10th

Answer :

15 cot A = 8, find sin A and sec A.

Cot A =8/15

By Pythagoras Theorem

AC² =AB² +BC²

AC =

AC = 17x

Sin A = 15/17

Cos A =8/17 ⇒ Sec A = 17/8

By Pythagoras Theorem

QR = cm

QR = 5 cm

tan P = 5/12

cot R =5/12

tan P -Cot R = 5/12 – 5/12 = 0

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUSDraw a line segme NEXTHow many terms of

Related Videos

Heights and Distances - I54 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

view all courses