Find x in terms o

We have,

(x – c) [ax + bx – 2ab] = 2c (x² – bx – ax + ab)

ax² + bx² – 2bx – acx – bcx + 2abc = 2cx² – 2bcx – 2cax + 2abc

ax² + bx² – 2cx² – 2abx + bcx + cax = 0

x² (a + b – 2c) + x (- 2ab + bc + ca) = 0

∴ x = 0

Or x (a + b – 2c) + (- 2ab + bc + ca) = 0

∴