Q. 254.2( 5 Votes )

# Find the area of

Answer : The quadrilateral is divided into two triangles ABC and ACD.

Area of the quadrilateral ABCD = Area of triangle ABC + Area of triangle ACD.

Area of triangle ABC =

1/2 [x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]

= 1/2 [-3(-4 + 1) + -2(-1 + 1) + 4(-1 + 4)]

= 1/2 [9 + 0 + 12]

= 21/2 sq. units

Area of triangle ACD =

1/2 [x1(y3 – y4) + x3(y4 – y1) + x4(y1 – y3)]

= 1/2 [-3(-1 - 4) + 4(4 + 1) + 3(-1 + 1)]

= 1/2 [15 + 20 + 0]

= 35/2 sq. units

Area of the quadrilateral = (21/2) + (35/2)

= (56/2)

= 28 sq. units

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Basics of Coordinate Geometry53 mins  Distance Formula52 mins  Doubt Session47 mins  Section Formula53 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 