Answer :
Given: p(1 + √3) = 0, p(1 – √3) = 0
Concept Used:
A second–degree polynomial is given by,
p(x) = ax2 + bx + c
Explanation:
Since we know that p(1 + √3) = 0
∴ if x = 1 + √3 is substituted in p(x) then it satisfies the equation
⇒ x – (1 + √3) = 0 , and ((x – 1) – √3) is one factor of p(x)
And p(1 – √3) = 0 is given
⇒ if x = 1 – √3 is substituted in p(x) then it satisfies the equation
⇒ x – (1 – √3) = 0, and ((x – 1) + √3) is one factor of p(x)
⇒ since, ((x – 1) – √3) and ((x – 1) + √3) are the factors of p(x), it can be written as follows
⇒ p(x) = ((x – 1) – √3)((x – 1) + √3)
⇒ p(x) = (x – 1 – √3)(x – 1 + √3)
⇒ p(x) = x2 – x + √3x –x + 1 – √3 – √3x + √3 – 3
⇒ p(x) = x2 – 2x – 2
∴ x2 – 2x – 2 is the second degree polynomial which satisfies p(1 + √3) = 0 and p(1 – √3) = 0.
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