Answer :
We know that-
So first 3 terms are
Also, it is given that their value are 729, 7290 and 30375
Therefore,
…(1)
…(2)
…(3)
Dividing (1) by (2)
…(4)
Dividing (2) by (3)
…(5)
Dividing (4) by (5)
⇒ 12(n-1) = 10n
⇒ 12n-12 = 10n
⇒ 2n = 12
⇒ n = 12/2
∴ n = 6
Putting n = 6 in (1)
an = 729
⇒ a6 = 729
⇒ a6 = (3)6
∴ a = 3
Putting a = 3, n = 6 in (5)
⇒ 6b = 30
⇒ b = 30/6
∴ b = 5
Thus, a = 3, b = 5 and n = 6.
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