# Evaluate: <

Let, I = I = I = …(1)

Using the property of definite integral: I = I = { sin (π/2 – x) = cos x}

I = …(2)

Adding equation 1 and 2, we get –

2I = Using algebra of integrals we have –

2I = 2I = I = π/12

OR

Let, I = I = I = Let, I1 = and I2 = I = 3I1 + I2 …(1)

First, we will calculate I1 and I2 and then add both to get the answer.

Calculation of I1 :

Let x2 -9x + 20 = u

du = (2x - 9)dx

(2x - 9)dx = du

I1 = I1 = + C1

I1 = ...(2)

Calculation of I2 :

I2 = I2 = I2 =  Use the formula: I2 = …(3)

From equation 1, 2 and 3 we have –

I = 3( ) + I = Rate this question :

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