Q. 255.0( 1 Vote )

# Draw a right tria

Given:

Sides (other than hypotenuse) = 8 cm and 6 cm

Steps of Construction:

1. Draw a line segment BC = 8 cm.

2. Construct B = 90°.

3. From B extend the line till A, to form BA.

4. Join AC. ∆ABC is the required triangle.

5. Now make an acute CBX, below BC.

6. Along BX, mark 4 ( 4 ˃ 3 in 3/4) points, B1, B2, B3 and B4 such that, BB1 = BB2 = BB3 = BB4.

7. Join CB4.

8. From B3, draw B3D such that, B3DCB3 where D is a point that lies on the line BC.

9. From D, draw ED such that, EDAC where E is a point that lies on the line.

∆EBD is the required triangle with the sides that are 3/4 of corresponding sides of ∆ABC.

Justification:

Cleary by construction,

And, DECA

∆EBD~∆ABC

Hence,

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