Answer :

let x units of F1 and y units of F2 be mixed. Therefore, we have to minimize the cost C = 5x + 6y

Now according to the given conditions, the equations are

4x + 3y≥80

3x + 6y≥100

x≥0, y≥0

Solving the equations to get the points of intersection

From the graph, we can see that the common area is on and beyond the points a, b and d

Now finding the cost

From the above equations, we can see that the minimum occurs at point b with the cost of 124

Therefore, number of units are

F1 = 12

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