Answer :

let x units of F1 and y units of F2 be mixed. Therefore, we have to minimize the cost C = 5x + 6y

Now according to the given conditions, the equations are


4x + 3y≥80


3x + 6y≥100


x≥0, y≥0


Solving the equations to get the points of intersection






From the graph, we can see that the common area is on and beyond the points a, b and d


Now finding the cost





From the above equations, we can see that the minimum occurs at point b with the cost of 124


Therefore, number of units are


F1 = 12



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