Answer :

Using Bernoulli’s Trial P(Success=x) = nCx.px.q(n-x)


x=0, 1, 2, ………n and q = (1-p)


As the die is thrown 5 times the total number of outcomes will be .


And we know that the favourable outcomes of getting at least 4 successes will be, either getting 1, 3 or 5 i.e., 1/6 probability of each, total, probability, p = ,q =


The probability of success is and of failure is also



the probability of getting at least 4 successes =


P(4)+P(5)


5C4()4()1 +5C5()5()0


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