Answer :

Using Bernoulli’s Trial P(Success=x) = nCx.px.q(n-x)

x=0, 1, 2, ………n and q = (1-p)

As the die is thrown 5 times the total number of outcomes will be .

And we know that the favourable outcomes of getting at least 4 successes will be, either getting 1, 3 or 5 i.e., 1/6 probability of each, total, probability, p = ,q =

The probability of success is and of failure is also

the probability of getting at least 4 successes =


5C4()4()1 +5C5()5()0

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