Answer :

Let’s find out the probability of getting ‘9’ from throw of a pair of dice first:

9 can be obtained in the given 4 cases

[(3,6), (4,5), (5,4), (6,3)]

Getting 9

Not getting 9

B will win when A won’t get 9 in his/her throw and B will get 9 in his/her throw, i.e. B wins after 1 round of throws, P

Now then,

P(B wins) = P(Getting 9 in 2nd throw) + P(Getting 9 in 4th throw) + P(Getting 9 in 6th throw) + . . . . . . .

GP (Geometric Progression)

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