The diagonals AC A. 70°

B. 90°

C. 80°

D. 100°

Given that,

∠ABD = ∠ABP = 50°

∠PBC +∠ABP = 90° (Each angle of a rectangle is a right angle)

∠PBC = 40°

Now,

PB = PC (Diagonals of a rectangle are equal and bisect each other)

Therefore,

∠BCP = 40° (Equal sides has equal angle)

In triangle BPC,

∠BPC + ∠PBC + ∠BCP = 180° (Angle sum property of a triangle)

∠BPC = 100°

∠BPC + ∠DPC = 180° (Angles in a straight line)

∠DPC = 180^o – 100^o

= 80°