Q. 24

The common difference of an A.P., the sum of whose n terms is Sn, isA. Sn – 2Sn–1 + Sn–2B. Sn – 2Sn–1– Sn–2C. Sn – Sn–2D. Sn – Sn–1

an is the nth term of an A.P and a n–1 is the (n–1)th term of an A.P,

d = common difference, Sn = sum of n terms of an A.P

d= an – an–1

But an= Sn – Sn–1

And an–1= Sn–1 – Sn–2

So d= Sn – Sn–1 – (Sn–1 – Sn–2)

d= Sn – 2 Sn–1 + Sn–2

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